Obtain the quadratic or the cubic polynomial as the case may be in the standard form with the following coefficients: $a=2, b=3, c=-5, d=0$.
(N/A) The standard form of a cubic polynomial is given by $P(x) = ax^3 + bx^2 + cx + d$.
Given the coefficients $a=2, b=3, c=-5$,and $d=0$.
Substituting these values into the standard form,we get:
$P(x) = 2x^3 + 3x^2 + (-5)x + 0$.
Therefore,the required polynomial is $2x^3 + 3x^2 - 5x$.
Given the coefficients $a=2, b=3, c=-5$,and $d=0$.
Substituting these values into the standard form,we get:
$P(x) = 2x^3 + 3x^2 + (-5)x + 0$.
Therefore,the required polynomial is $2x^3 + 3x^2 - 5x$.
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